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0 "" {TEXT -1 175 "On peut le deviner a partir du fait que lorsqu'on p
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r" }{TEXT -1 74 ") passe de la valeur 1 a la valeur 0 pendant que l'ar
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{TEXT -1 335 "La courbe elle-meme est reunion de 4 morceaux symetrique
s de celui ci-dessus. Puisque cos(T) passe de la valeur 1 a 0 lorsque \+
T varie de 0 a Pi/4, on doit prendre r=cos(t/4), t variant de 0 a 2*Pi
, pour avoir le morceau de courbe ci-dessus, et faire varier t de 0 a \+
4*(2*Pi) pour avoir les 4 morceaux qui constituent la courbe entiere.
" }}}}{SECT 1 {PARA 3 "" 0 "" {TEXT 272 12 "Exercice 12." }}{EXCHG 
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c, lorsqu'on se rapproche de ces points, la variation de f, qui est ap
prochee par la longueur du gradient, est de plus en plus lente; or la \+
variation de f entre deux contours est constante. Voici le graphe de f
 en restriction a l'axe OX: " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 
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}}}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 229 "Le developpement de Taylor de
 f a l'ordre 2 en (0,0) s'ecrit y^2-x^2, qui est l'equation des deux d
roites : y-x=0, y+x=0. On peut donc s'attendre a ce que la courbe elle
-meme soit proche de ces deux droites au voisinage de (0,0)." }}}}}
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